10TH CBSE Maths QUIZ— Statistics 10 MCQ Tests × 10 Questions = 100 Questions

Class 10 Mathematics — Statistics

10 MCQ Tests × 10 Questions = 100 Questions

Questions are based on the uploaded Statistics MCQ question-and-answer PDF. fileciteturn18file0L2-L13

Answer protection: Submit a test to display the score and highlight correct/wrong options. The written “Correct Answer” line inside each question remains hidden until the password is entered.

TEST 1

Statistics — MCQ Test 1

10 Questions

Q1. The relation between mean, mode and median is:

AMode = (3 × mean) - (2 × median)BMode = (3 × median) - (2 × mean)CMode = (3 × mean) - (2 × mode)DMode = (3 × median) - (2 × mode) 1 Mark Ans: B Mode = (3 × median) - (2 × mean)

Correct Answer: Option B — Mode = (3 × median) - (2 × mean)

Q2. For the following distribution: Mark 60-70 70-80 80--90 90-100 100-110 Frequency 13 10 15 8 11 The upper limit of the median class is:

A10B90C80D100 1 Mark Ans: B 90 Siolution: Mark 60-70 70-80 80-90 90-100 100-110 Frequency 13 10 15 8 11 Cumulative 13 23 38 46 57 Here N = 57 ⇒ N 2 = 28.5 ∴ Median class is 80-90 The upper limit of the median class is 90.

Correct Answer: Option B — 90

Q3. Consider the following frequency distribution: Class 0-5 6-11 12-17 18-23 24-29 Frequency 13 10 15 8 11 The upper limit of the median class is

A16.5B18.5C18D17.5 1 Mark Ans: D 17.5 Solution: The given series is in indusive from. comverting in to exclusive from and preparing cumulative frequency tabla, we get Class Frequency Cumulative frequency -0.5-5.5 13 13 5.5-11.5 10 23 11.5-17.5 15 38 17.5-23.5 8 46 23.5-29.5 11 57 Here, N = 57 ⇒ N 2 = 28.5 The cumulative frequency just greater than 28.5 is 38. Hence, the median class is 11.5-17.5 ∴ Upper limit of the median class = 17.5

Correct Answer: Option D — 17.5 1 Mark Ans: D 17.5 Solution: The given series is in indusive from. comverting in to exclusive from and preparing cumulative frequency tabla, we get Class Frequency Cumulative frequency -0.5-5.5 13 13 5.5-11.5 10 23 11.5-17.5 15 38 17.5-23.5 8 46 23.5-29.5 11 57 Here, N = 57 ⇒ N 2 = 28.5 The cumulative frequency just greater than 28.5 is 38. Hence, the median class is 11.5-17.5 ∴ Upper limit of the median class = 17.5

Useful Resource: CBSE Class 10 English

Q4. If the mean of a data is 27 and its median is 33. Then, the mode is:

A30B43C45D47 1 Mark Ans: C 45 Solution: Mean = 27 Median = 33 Mode = 3median - 2Mean = 3 × 33 - 2 × 27 = 99 - 54 = 45

Correct Answer: Option C — 45

Q5. The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 2, 1, 3, 2, 3. The median of the data is:

A2B3C2.5D1 1 Mark Ans: C 2.5 Solution: Arranging the given data in ascending order, we get 0, 1, 2, 2, 2, 3, 3, 4, 5, 6 Here, n = 10, which is even. ∴ Median = 1 2 ( n 2 )th term + ( n 2 + 1)th term = 1 2 [5th term + 6th term ] ⇒ Median = 1 2 [2 + 5] = 5 2 = 2.5

Correct Answer: Option C — 2.5

Q6. The arithmetic mean of 1, 2, 3, ..., n is: 1 Mark Exam Paper . Test / Exam Name: Statistics [ ]

An+12Bn−12Cn2Dn2+1 Ans:An+12 Solution:Arithmetic mean of 1, 2, 3, ......, n =1+2+3+......+nn = n(n+1)2 n =n+12Hence, the correct option is (a)

Correct Answer: Option A — n+12

Useful Resource: Ravi Test Papers .in

Q7. The mean of a discrete frequency distribution xf ; i= 1, 2, ……, n is given by:

A∑fixi ∑fiB1n∑ni=1fixiC1 n∑ni=1fixi 1n∑ni=1xiD1 n∑ni=1fixi 1n∑ni=1i

Correct Answer: Option A — ∑fixi ∑fi

Q8. Choose the correct answer from the given four options:Consider the following frequency distribution:Class 0-5 6-11 12-27 18-23 24-29Frequency 13 10 15 8 11 The upper limit of the median class is:

A17B17.5C18D18.5

Correct Answer: Option B — 17.5

Q9. For a frequency distribution, mean, median and mode are connected by the relation:

AMode = 3 Mean – 2 Median.BMode = 2 Median – 3 Mean.CMode = 3 Median – 2 Mean.DMode = 3 Median + 2 Mean.

Correct Answer: Option C — Mode = 3 Median – 2 Mean.

Useful Resource: CBSE Class 10 Maths

Q10. In the formula ˉx=a+∑fidi ∑fi ,di represents:

Aa+xiBdi=xi−aCa−xiDx1+a

Correct Answer: Option B — di=xi−a

TEST 2

Statistics — MCQ Test 2

10 Questions

Q1. In the formula ˉx=a+h1 N∑fiui , for finding the mean of grouped frequency distribution ui=

Axi+a hBh(xi−a)Cxi−a hDa−xi h

Correct Answer: Option C — xi−a h

Q2. If ∑fixi=625 and ∑fi=25 then the value of ˉx is:

A26B63C64D25

Correct Answer: Option D — 25

Q3. One of the method of determining mode is:

AMode = 2Median - 3MeanBMode = 2 Median + 3 MeanCMode = 3 Median - 2 MeanDMode = 3 Median + 2 Mean

Correct Answer: Option C — Mode = 3 Median - 2 Mean

Useful Resource: CBSE Class 10 Social Science

Q4. The mean of 1, 3, 4, 5, 7, 4 is m. The number 3, 2, 2, 4, 3, 3, p have mean m – 1 and median q. Then p + q =

A4B5C6D7

Correct Answer: Option D — 7

Q5. The mean of all the factors of 24 is:

A6.5B7C7.5D24

Correct Answer: Option C — 7.5

Q6. If ∑fisi=1860 and ∑fi=30 then the value of ˉx is:

A26B64C62D63

Correct Answer: Option C — 62

Useful Resource: RAVI MATHS TUITION CENTRE YouTube

Q7. The arithmetic mean and mode of a data are 24 and 12 respectively, then its median is:

A25B18C20D22

Correct Answer: Option C — 20

Q8. If the difference of mode and median of a data is 24, then the difference of median and mean is:

A12B24C8D36

Correct Answer: Option A — 12

Q9. If the mean of first n natural numbers is 5n 9, then n =

A5B4C9D10

Correct Answer: Option C — 9

Useful Resource: CBSE Class 10 Science

Q10. Look at the frequency distribution table given below:Class interval 35-45 45-55 55-65 65-75Frequency 8 12 20 10 The median of the above distribution is:

A56.5B57.5C58.5D59

Correct Answer: Option C — 58.5

TEST 3

Statistics — MCQ Test 3

10 Questions

Q1. For the following distribution:Class 60-70 70-80 80-90 90-100 100-110Frequency 13 10 15 8 11 The lower limit of the modal class is:

A100B80C90D70

Correct Answer: Option B — 80

Q2. The marks obtained by 9 students in Mathematics are 59, 46, 30, 23, 27, 44, 52, 40 and 29. The median of the data is:

A30B40C29D35

Correct Answer: Option B — 40

Q3. In a data, if l = 60, h = 15, f = 16, f = 6, f = 6, then the mode is:

A67.5B72C60D62

Correct Answer: Option A — 67.5

Useful Resource: All Subjects Study Materials

Q4. Mode =?

Axk+h. (fk−1−fk) (2fk−fk−1−fk+1)Bxk+h. (fk−fk−1) (2fk−fk−1−fk+1)Cxk+h. (fk−fk−1) (fk−2fk−1−fk−1)Dxk+h. (fk−fk−1) (fk−fk−1−2fk+1)

Correct Answer: Option B — xk+h. (fk−fk−1) (2fk−fk−1−fk+1)

Q5. Mode of 2, 3, 4, 5, 0, 1, 3, 3, 4, 3 is 3:

ATrueBFalseCNeitherDNone

Correct Answer: Option A — True

Q6. The median of first 10 prime numbers is:

A11B12C13D14

Correct Answer: Option B — 12

Useful Resource: Ravi Test Papers

Q7. Which of the following is not a measure of central tendency?

AStandard deviationBMedianCArithmetic meanDMode

Correct Answer: Option A — Standard deviation

Q8. The median and mode of a frequency distribution are 26 and 29 respectively. Then, the mean is:

A27.5B24.5C28.4D25.8

Correct Answer: Option B — 24.5

Q9. The mean of first n odd natural number is:

An+12Bn2CnDn2

Correct Answer: Option C — n

Useful Resource: CBSE Class 10 English

Q10. In formula ¯x=a+h∑fiui ∑fi for finding the mean,ui=

Axi-a hBa−xi hCh(xi−a)Dxi+a h

Correct Answer: Option A — xi-a h

TEST 4

Statistics — MCQ Test 4

10 Questions

Q1. The mean of first n odd natural numbers is n2 81, then n =

A9B81C27D18

Correct Answer: Option B — 81

Q2. Which of the following cannot be determined graphically?

AMeanBMedianCModeDNone of these

Correct Answer: Option A — Mean

Q3. The mean of ‘n’ observations is x̄. If the first item is increased by 1, second by 2 and so on, then the new mean is:

Ax̄ − (n−1)/2Bx̄Cx̄ − (n+1)/2Dx̄ + (n+1)/2

Correct Answer: Option D — x̄ + (n+1)/2

Useful Resource: Ravi Test Papers .in

Q4. In the formul ˉx=a+h(∑fiui ∑fi ) a stands for:

AAssumed meanBClass size CClass markDMean

Correct Answer: Option A — Assumed mean

Q5. For the following distribution:Mark 60-70 70-80 80-90 90-100 100-110Frequency 10 15 12 20 9 The sum of lower limits of the median class and modal class is:

A20B180C170D190

Correct Answer: Option C — 170

Q6. In formula ˉx=a+h(∑f1ui ∑fi ),h, stands for:

AClass sizeBClass mark CMeanDNone of these

Correct Answer: Option A — Class size

Useful Resource: CBSE Class 10 Maths

Q7. While computing mean of grouped data, we assume that the frequencies are:

AEvenly distributed over all the classes.BCentred at the classmarks of the classes.CCentred at the upper limits of the classes.DCentred at the lower limits of the classes.

Correct Answer: Option B — Centred at the classmarks of the classes.

Q8. The modal value is the value of the variate which divides the total frequency into two equal parts:

ATrueBFalseCNeitherDEither

Correct Answer: Option B — False

Q9. A child says that the median of 3, 14, 18, 20, 5 is 18. What concept did the child miss about finding the median?

AThe order of numbersB14C18DNone of these

Correct Answer: Option A — The order of numbers

Useful Resource: CBSE Class 10 Social Science

Q10. The median of a frequency distribution is found graphically with the help of:

AA histogram.BA frequency curve.CA frequency polygon.DOgives

Correct Answer: Option D — Ogives

TEST 5

Statistics — MCQ Test 5

10 Questions

Q1. While computing the mean of the grouped data, we assume that the frequencies are:

AEvenly distributed over the classes.BCentred at the class marks of the classes.CCentred at the lower limits of the classes.DCentred at the upper limits of the classes.

Correct Answer: Option B —

Q2. If ∑fiui=29,∑fi=30,a=47.5 and h=15, then the value of ˉx is:

A26B63C62D64

Correct Answer: Option C — 62

Q3. The arithmetic mean of a set of 40 values is 65. If each of the 40 values is increased by 5, what will be the mean of the set ofnew values:

A60B65C70D50

Correct Answer: Option C — 70

Useful Resource: RAVI MATHS TUITION CENTRE YouTube

Q4. The percentage of marks obtained by 100 students in an examination are as follows:Mark 30-35 35-40 40-45 45-50 50-55 55-60 60-65Frequency 10 15 18 22 23 8 4 The median class is:

A35-40B45-50C40-45D50-55

Correct Answer: Option B — 45-50

Q5. The mean of the data when∑fidi=−500,∑fi=100 and a=125 is:

A120B100C-500D125

Correct Answer: Option A — 120

Q6. The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 3, 1, 3, 2, 3. The median of the data is:

A2.5B3C1D2

Correct Answer: Option B — 3

Useful Resource: CBSE Class 10 Science

Q7. ∑(xi−ˉx) is equal to:

A0B2C1D-1

Correct Answer: Option A — 0

Q8. For any collection of n items,∑x −¯x=

An¯xB(n+1)¯xC(n−1)¯xD0

Correct Answer: Option C — (n−1)¯x

Q9. The mean of the first 10 natural odd numbers is:

A10B9C11D12

Correct Answer: Option A — 10

Useful Resource: All Subjects Study Materials

Q10. If the mean of 6, 7, x, 8, y, 14 is 9, then:

Ax + y = 21Bx + y = 19Cx - y = 19Dv - y = 21

Correct Answer: Option B — x + y = 19

TEST 6

Statistics — MCQ Test 6

10 Questions

Q1. The formula for the median of grouped data is:

Al + h × (N/2 − cf)/fBl + h × (cf − N/2)/fCl − h × (N/2 − cf)/fDNone of these

Correct Answer: Option A — l + h × (N/2 − cf)/f

Q2. The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 2, 1, 3, 2, 3. The mode of the data is:

A3B2C4D1

Correct Answer: Option B — 2

Q3. The arithmetic mean of the following data is 53.Class 0-20 20-40 40-60 60-80 80-100Frequency 12 15 32 P 13 The value of p is:

A17B20C27D28

Correct Answer: Option D — 28

Useful Resource: Ravi Test Papers

Q4. In the formula ¯X=a+∑fidi ∑fi for finding the mean of grouped data di’s are deviations from a of:

Alower limits of classes.Bupper limits of classes.Cmid-points of classes.Dfrequency of the class marks .

Correct Answer: Option C — mid-points of classes.

Q5. The algebraic sum of the deviations of a frequency distribution from its mean is:

AAlways positive.BAlways negative.C0.DA non-zero number.

Correct Answer: Option C — 0.

Q6. One of the methods of determining mode is:

AMode = 2 Median – 3 Mean.BMode = 2 Median + 3 Mean.CMode = 3 Median – 2 Mean.DMode = 3 Median + 2 Mean.

Correct Answer: Option C — Mode = 3 Median – 2 Mean.

Useful Resource: CBSE Class 10 English

Q7. If the mode of the data 16, 15, 17, 16, 15, x, 19, 17, 14 is 15, then x =

A15B16C17D19

Correct Answer: Option A — 15

Q8. The mode of a frequency distribution is obtained graphically from:

AA frequency curve.BA frequency polygon.CA histogram.DAn ogive.

Correct Answer: Option C — A histogram.

Q9. The mean of the first 10 multiples of 6 is:

A33B3.3C35D34

Correct Answer: Option A — 33

Useful Resource: Ravi Test Papers .in

Q10. Consider the following frequency distribution:Class 0-10 10-20 20-30 30-40 40-50 50-60Frequency 3 9 15 30 18 5 The modal class is:

A10-20B20-30C30-40D50-60

Correct Answer: Option C — 30-40

TEST 7

Statistics — MCQ Test 7

10 Questions

Q1. The mode of a frequency distribution can be determined graphically from:

AHistogram.BFrequency polygon.COgive.DFrequency curve.

Correct Answer: Option C — Ogive.

Q2. If 35 is removed from the data : 30, 34, 35, 36, 37, 38, 39, 40, then the median increases by:

A2B1.5C1D0.5

Correct Answer: Option D — 0.5

Q3. Mean – Mode =

A3(Mean – Mode)B3(Median – Mean)C3(Mean – Median)D3(Mode – Mean)

Correct Answer: Option C — 3(Mean – Median)

Useful Resource: CBSE Class 10 Maths

Q4. In a data, if l = 40, h = 15, f = 7, f = 3, f = 6, then the mode is:

A62B82C52D72

Correct Answer: Option C — 52

Q5. The percentage of marks obtained by 100 students in an examination are as follows:Mark 30-35 35-40 40-45 45-50 50-55 55-60 60-65Frequency 14 16 18 23 18 8 3 The median class is:

A45 - 50B50-55C40 - 45DNone of these

Correct Answer: Option A — 45 - 50

Q6. Consider the frequency distribution of the heights of 60 students of a class:Height (in cm) No. of Students Cumulative Frequency150-155 16 16155-160 12 28160-165 9 37165-170 7 44170-175 10 54175-180 6 60 The sum of the lower limit of the modal class and the upper limit of the median class is:

A310B315C320D330

Correct Answer: Option B — 315

Useful Resource: CBSE Class 10 Social Science

Q7. The relationship between mean, median and mode for a moderately skewed distribution is:

AMode = 2 Median - 3 Mean.BMode = Median - 2 Mean.CMode = 2 Median - Mean.DMode = 3 Median -2 Mean.

Correct Answer: Option D — Mode = 3 Median -2 Mean.

Q8. The arithmetic mean of 1, 2, 3, 4, …, n is:

An/2Bn(n+1)/2C(n+1)/2D(n−1)/2

Correct Answer: Option A — n/2

Q9. If the mean and median of a set of numbers are 8.9 and 9 respectively, then the mode will be:

A7.2B8.2C9.2D10.2

Correct Answer: Option C — 9.2

Useful Resource: RAVI MATHS TUITION CENTRE YouTube

Q10. For the following distribution:Class: 0-5 5-10 10-15 15-20 20-25Frequency: 10 15 12 20 9 the sum of the lower limits of the median and modal class is:

A15B25C30D35

Correct Answer: Option B — 25

TEST 8

Statistics — MCQ Test 8

10 Questions

Q1. If the arithmetic mean of 7, 8, x, 11, 14 is x, then x =

A9B9.5C10D10.5

Correct Answer: Option C — 10

Q2. In the formula, ˉx=

A+∑fidi ∑fi for finding the mean of the grouped data, the d's are the deviations from A of: ALower limits of the classesBUpper limits of the classesCMidpoints of the classesDNone of these

Correct Answer: Option C — Midpoints of the classes

Q3. The marks obtained by 9 students in Mathematics are 59, 46, 31, 23, 27, 40, 52, 35 and 29. The mean of the data is:

A38B30C23D41

Correct Answer: Option A — 38

Useful Resource: CBSE Class 10 Science

Q4. The mean and mode of a frequency distribution are 28 and 16 respectively. The median is:

A22B23.5C24D24.5

Correct Answer: Option C — 24

Q5. The empirical relationship between the three measures of central tendencies is:

ANone of theseB3 mean = median + 2 modeC3 mode = mean + 2 medianDMode = 3 median - 2 mean

Correct Answer: Option D — Mode = 3 median - 2 mean

Q6. Choose the correct answer from the given four options:The times, in seconds, taken by 150 athletes to run a 110 m hurdle race are tabulated below:Class 13.8-1414-14.214.2-14.414.4-14.614.6-14.814.8-15Frequency2 4 5 71 48 20 The number of athletes who completed the race in less then 14.6 seconds is:

A11B71C82D130

Correct Answer: Option C — 82

Useful Resource: All Subjects Study Materials

Q7. If the mean of observations x, x, …, x is ˉx, then the mean of x + a, x + a,…, x + a is

AaˉxBˉx−aCˉx+aDˉxa

Correct Answer: Option C — ˉx+a

Q8. The wickets taken by a bowler in 10 cricket matches are 2, 6, 4, 5, 0, 3, 1, 3, 2, 3. The mode of the data is:

A4B3C1D2

Correct Answer: Option B — 3

Q9. Mode is:

ALeast frequent value.BMiddle most value.CMost frequent value.DNone of these.

Correct Answer: Option C — Most frequent value.

Useful Resource: Ravi Test Papers

Q10. Which one of the following is not a measure of central tendency?

AArithmetic meanBMedianCModeDVariance

Correct Answer: Option D — Variance

TEST 9

Statistics — MCQ Test 9

10 Questions

Q1. Consider the following frequency distribution:Class: 0-5 6-11 12-17 18-23 24-29Frequency: 13 10 15 8 11 The upper limit of the median class is:

A17B17.5C18D18.5

Correct Answer: Option B — 17.5

Q2. If x s are the midpoints of the class intervals of a grouped data, f s are the corresponding frequency and ˉx is the mean, then ∑fi(xi−ˉx)=?

A1B0C-1D2

Correct Answer: Option B — 0

Q3. Median divides the total frequency into _____ equal parts:

A2B3C4DNone of these

Correct Answer: Option A — 2

Useful Resource: CBSE Class 10 English

Q4. The marks obtained by 9 students in Mathematics are 59, 46, 30, 23, 27, 40, 52, 35 and 29. The median of the data is:

A29B30C35D40

Correct Answer: Option C — 35

Q5. The median of first 10 prime numbers is:

A13B12C11D12.5

Correct Answer: Option B — 12

Q6. For the following distribution38Below 10 20 30 40 50 60Frequency 3 12 27 57 75 80 the modal class is:

A50 – 60B20 – 30C40 – 50D30 – 40

Correct Answer: Option D — 30 – 40

Useful Resource: Ravi Test Papers .in

Q7. Consider the table: Class interval 10-14, 14-18, 18-22, 22-26, 26-30; Frequency 5, 11, 16, 25, 19. The mode is:

A23.5B24C24.4D25

Correct Answer: Option C — 24.4

Q8. The marks of 20 students in a test were as follows:5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20 The mode is:

A20B10C15D25

Correct Answer: Option C — 15

Q9. Choose the correct answer from the given four options:The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of agrouped data gives its:

AMean.BMedian.CMode.DAll the three above.

Correct Answer: Option B — Median.

Useful Resource: CBSE Class 10 Maths

Q10. If the mean of first n natural number is 15, then n =

A15B30C14D29

Correct Answer: Option D — 29

TEST 10

Statistics — MCQ Test 10

10 Questions

Q1. The mean of the first 10 prime numbers is:

A1.29B12.9C129D11.9

Correct Answer: Option B — 12.9

Q2. /and the mean of the distribution is 7, then the value of p is:

A13B12C14D15

Correct Answer: Option C — 14

Q3. In the formula x̄ = a + h(Σfiui/Σfi), for finding the mean of grouped frequency distribution, ui =

A(xi + a)/hBh(xi − a)C(xi − a)/hD(a + xi)/h

Correct Answer: Option C — (xi − a)/h

Useful Resource: CBSE Class 10 Social Science

Q4. Choose the correct answer from the given four options:For the following distribution:Class 0-5 5-10 10-15 15-20 20-25Frequency 10 15 12 20 9 the sum of lower limits of the median class and modal class is:

A15B25C30D35

Correct Answer: Option B — 25

Q5. State true or false:The mode is the most frequently occurring observation:

ATrueBFalseCCan't determineDNone of these

Correct Answer: Option A — True

Q6. If the median of the data : 6, 7, x – 2, x, 17, 20, written in ascending order, is 16. Then x =

A15B16C17D18

Correct Answer: Option C — 17

Useful Resource: RAVI MATHS TUITION CENTRE YouTube

Q7. If the arithmetic mean of x, x + 3, x + 6, x + 9, and x + 12 is 10, then x =

A1B2C6D4

Correct Answer: Option A — 1

Q8. The mode of 4, 5, 6, 8, 5, 4, 8, 5, 6, x, 8 is 8. The value of x is:

A6B8C5D4

Correct Answer: Option B — 8

Q9. Formula to find mode is:

AMean - 2 MedianB3 Median - 2 MeanC3 Median - MeanDMean + Median

Correct Answer: Option C — 3 Median - Mean

Useful Resource: CBSE Class 10 Science

Q10. The mean of the first 10 composite numbers is:

A12.2B11.4C11.2D112

Correct Answer: Option C — 11.2

Useful Ravi Resources

• Ravi Test Papers
• CBSE Class 10 Maths
• CBSE Class 10 Science
• CBSE Class 10 English
• CBSE Class 10 Social Science
• All Subjects Study Materials
• Ravi Test Papers .in
• RAVI MATHS TUITION CENTRE YouTube

Answer password: RAVI2026. This password is embedded in client-side JavaScript, so it is not secure against source inspection.